CE Nov 2023 MSTE Problem 5: Calculate Excavator's Hourly Production in Cubic Meters 🚧

CE NOV 2023 - Find the expected production in loose cu.m (LCM) per hour of a small hydraulic excavator. Heaped bucket capacity is 0.57 m^3 .The material is sand and gravel with a bucket fill factor of 0.95 .Job efficiency is 50 min/hr .Average depth of cut is 4.3 m. max. depth of cut is 6.1 m and average swing is 90<br /><br />Hint: Production = C * S * V * B * E<br /><br />Cycle output = 250 cycles per 60 min<br />Swing depth factor = 1.0<br />-<br />CE Board MSTE Problem 5 (Mathematics, Surveying, Transportation, and Construction) - CE Nov 2023<br />-<br />paki pindot po sa "LIKE" button mga Engr.<br />and click SUBSCRIBE na rin po if hindi pa po kayo naka "SUBSCRIBE"<br /><br />Maraming salamat po sa inyo mga Engineers and Future Engineers.<br />mabuhay po kayong lahat.<br />-<br />FB Page - https://www.facebook.com/MrComputerCiviLEngineer<br />Tiktok - https://www.tiktok.com/@SolUsmanJr<br />-------------<br />CREDIT:<br />-------------<br />Soundtrack:<br />Ace Attorney Dual Destinies - Apollo Justice (I'm fine)<br />Ace Attorney Spirit of Justice (Credit Theme)<br /><br />Avatar:<br />SuperME Cartoon Avatar Maker (mobile app)<br /><br />Reference:<br />"Licensure Exams for Civil Engineering" by BESAVILLA<br />"CE Reference for Licensure Examination" by GILLESANIA<br />-<br />#SolUsmanJr<br />#ceboardexam <br />#civilengineeringlicensureexam