Division of Polynomials or algebraic expressions | Basic of Algebra | MathOguide
Division of Polynomials or algebraic expressions | Basic of AlgebraSteps for Long Division of Polynomials:Let's take a general polynomial division example:Di...
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Division of Polynomials or algebraic expressions | Basic of Algebra
Steps for Long Division of Polynomials:
Let's take a general polynomial division example:
Divide by .
Step-by-Step Solution:
Step 1: Set up the division.
Dividend:
Divisor:
Start with the division symbol:
\frac{3x^3 + 5x^2 - 2x + 7}{x + 2}
Step 2: Divide the first term of the dividend by the first term of the divisor.
Divide by , which gives .
Now, write as the first term of the quotient.
Step 3: Multiply the divisor by the first term of the quotient.
Multiply by :
3x^2 \cdot (x + 2) = 3x^3 + 6x^2
Step 4: Subtract this result from the dividend.
Now subtract from :
(3x^3 + 5x^2 - 2x + 7) - (3x^3 + 6x^2) = -x^2 - 2x + 7
Step 5: Repeat the process with the new polynomial.
Now, divide the first term of the new polynomial by , which gives .
Write as the next term in the quotient.
Step 6: Multiply the divisor by the new term of the quotient.
Multiply by :
-x \cdot (x + 2) = -x^2 - 2x
Step 7: Subtract this result from the current polynomial.
Subtract from :
(-x^2 - 2x + 7) - (-x^2 - 2x) = 7
Step 8: Repeat the process one last time.
Now divide the constant term by , but since is a constant and cannot be divided by , it becomes the remainder.
Thus, the quotient is and the remainder is .
Final Answer:
\frac{3x^3 + 5x^2 - 2x + 7}{x + 2} = 3x^2 - x + \frac{7}{x + 2}
#divisionofpolynomial #divisionofalgebra #algebra
Steps for Long Division of Polynomials:
Let's take a general polynomial division example:
Divide by .
Step-by-Step Solution:
Step 1: Set up the division.
Dividend:
Divisor:
Start with the division symbol:
\frac{3x^3 + 5x^2 - 2x + 7}{x + 2}
Step 2: Divide the first term of the dividend by the first term of the divisor.
Divide by , which gives .
Now, write as the first term of the quotient.
Step 3: Multiply the divisor by the first term of the quotient.
Multiply by :
3x^2 \cdot (x + 2) = 3x^3 + 6x^2
Step 4: Subtract this result from the dividend.
Now subtract from :
(3x^3 + 5x^2 - 2x + 7) - (3x^3 + 6x^2) = -x^2 - 2x + 7
Step 5: Repeat the process with the new polynomial.
Now, divide the first term of the new polynomial by , which gives .
Write as the next term in the quotient.
Step 6: Multiply the divisor by the new term of the quotient.
Multiply by :
-x \cdot (x + 2) = -x^2 - 2x
Step 7: Subtract this result from the current polynomial.
Subtract from :
(-x^2 - 2x + 7) - (-x^2 - 2x) = 7
Step 8: Repeat the process one last time.
Now divide the constant term by , but since is a constant and cannot be divided by , it becomes the remainder.
Thus, the quotient is and the remainder is .
Final Answer:
\frac{3x^3 + 5x^2 - 2x + 7}{x + 2} = 3x^2 - x + \frac{7}{x + 2}
#divisionofpolynomial #divisionofalgebra #algebra
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Nov 13, 2024
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