Solve for Plaintext M in RSA: Decoding Ciphertext C=20 with Public Key (e=3, n=33) π
Learn how to decrypt RSA ciphertext C=20 using the public key (e=3, n=33) to find the original message M. Step-by-step solution included!

Mindset Building
9.2K views β’ Jun 19, 2021

About this video
In a public key system, using RSA, You intercept the ciphertext C=20, sent to a user whose public key is e=3, n=33. what is the plaintext M?
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9.2K
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100
Duration
6:33
Published
Jun 19, 2021
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4.3
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