LeetCode Daily: Sort by Number of 1 Bits 🔥
Sort integers by count of 1 bits in binary; ties broken by value. Easy bit manipulation solution included.

RJ CODE BATTLE
6 views • Feb 25, 2026

About this video
In this problem, we sort the array based on the number of 1s in each number’s binary representation.
If two numbers have the same number of 1 bits, then sort them in ascending order.
💡 Approach:
Count set bits using bit manipulation or built-in function.
Use a custom comparator to sort.
⏱ Time Complexity:
O(n log n)
🧠 Space Complexity:
O(1)
👍 Simple explanation + clean solution.
Don’t forget to Like & Subscribe for daily LeetCode solutions!
#LeetCode #LeetCodeDaily #BitManipulation
If two numbers have the same number of 1 bits, then sort them in ascending order.
💡 Approach:
Count set bits using bit manipulation or built-in function.
Use a custom comparator to sort.
⏱ Time Complexity:
O(n log n)
🧠 Space Complexity:
O(1)
👍 Simple explanation + clean solution.
Don’t forget to Like & Subscribe for daily LeetCode solutions!
#LeetCode #LeetCodeDaily #BitManipulation
Video Information
Views
6
Duration
20:20
Published
Feb 25, 2026
Related Trending Topics
LIVE TRENDSRelated trending topics. Click any trend to explore more videos.
Trending Now