Learn Caesar Cipher Encryption & Decryption in Python 3 π
Discover how to implement Caesar Cipher in Python 3 with complete code examples for encrypting and decrypting messages. Show your support ππ» if this helps!

Arvin Babaei
57 views β’ Sep 22, 2020

About this video
Give a thumbs up ππ» if my code was useful to you.
Showing compilation and execution of my code in Python 3, which is capable of Encrypting, Decrypting, Brute force Attacking using Caesar Cipher cryptography.
#python #sublime #caesarcipher #cryptography
Develop a single program using any programming language (e.g. Java, Python, C++, etc) that:
a. Encrypts and decrypts a message using Cesarβs Cipher. The user encrypting the message is prompted to enter a message and then a key that indicates the displacement. The user decrypting the message is prompted to enter the encrypted message and the key.
b. Decrypts and displays all (26) possible solutions.
# Writen by Arvin Babaei
#Caesar Cipher cryptography code in Python 3
def encrypt(message, key):
encrypt_str = ''
for ch in message:
if ch.isupper():
encrypt_str += chr(ord('A') + ((ord(ch) - ord('A') + key + 26) % 26))
elif ch.islower():
encrypt_str += chr(ord('a') + ((ord(ch) - ord('a') + key + 26) % 26))
else:
encrypt_str += ch
return encrypt_str
def decrypt (message, key):
decrypt_str = ''
for ch in message:
if ch.isupper():
decrypt_str += chr(ord('A') + ((ord(ch) - ord('A') - key + 26) % 26))
elif ch.islower():
decrypt_str += chr(ord('a') + ((ord(ch) - ord('a') - key + 26) % 26))
else:
decrypt_str += ch
return decrypt_str
def brute (message, key):
brute_str = ''
for ch in message:
if ch.isupper():
brute_str += chr(ord('A') + ((ord(ch) - ord('A') - key + 26) % 26))
elif ch.islower():
brute_str += chr(ord('a') + ((ord(ch) - ord('a') - key + 26) % 26))
else:
brute_str += ch
return brute_str
if __name__ == '__main__':
while True:
input_message = input("Enter message: ")
option = input("Encrypt(E) or Decrypt(D) or Brute froce (B)?: ")
if option.lower() == 'e':
shift_amount = int(input("Enter key: "))
print(encrypt(input_message, shift_amount))
elif option.lower() == 'd':
shift_amount = int(input("Enter key: "))
print(decrypt(input_message, shift_amount))
elif option.lower() == 'b':
for shift_amount in range(26):
print ("using key: " + str(shift_amount))
print(brute(input_message, shift_amount))
else:
print("please enter valid input")
go_again = input("Go again?(Y/N):")
if go_again.lower() == 'n':
break;
Showing compilation and execution of my code in Python 3, which is capable of Encrypting, Decrypting, Brute force Attacking using Caesar Cipher cryptography.
#python #sublime #caesarcipher #cryptography
Develop a single program using any programming language (e.g. Java, Python, C++, etc) that:
a. Encrypts and decrypts a message using Cesarβs Cipher. The user encrypting the message is prompted to enter a message and then a key that indicates the displacement. The user decrypting the message is prompted to enter the encrypted message and the key.
b. Decrypts and displays all (26) possible solutions.
# Writen by Arvin Babaei
#Caesar Cipher cryptography code in Python 3
def encrypt(message, key):
encrypt_str = ''
for ch in message:
if ch.isupper():
encrypt_str += chr(ord('A') + ((ord(ch) - ord('A') + key + 26) % 26))
elif ch.islower():
encrypt_str += chr(ord('a') + ((ord(ch) - ord('a') + key + 26) % 26))
else:
encrypt_str += ch
return encrypt_str
def decrypt (message, key):
decrypt_str = ''
for ch in message:
if ch.isupper():
decrypt_str += chr(ord('A') + ((ord(ch) - ord('A') - key + 26) % 26))
elif ch.islower():
decrypt_str += chr(ord('a') + ((ord(ch) - ord('a') - key + 26) % 26))
else:
decrypt_str += ch
return decrypt_str
def brute (message, key):
brute_str = ''
for ch in message:
if ch.isupper():
brute_str += chr(ord('A') + ((ord(ch) - ord('A') - key + 26) % 26))
elif ch.islower():
brute_str += chr(ord('a') + ((ord(ch) - ord('a') - key + 26) % 26))
else:
brute_str += ch
return brute_str
if __name__ == '__main__':
while True:
input_message = input("Enter message: ")
option = input("Encrypt(E) or Decrypt(D) or Brute froce (B)?: ")
if option.lower() == 'e':
shift_amount = int(input("Enter key: "))
print(encrypt(input_message, shift_amount))
elif option.lower() == 'd':
shift_amount = int(input("Enter key: "))
print(decrypt(input_message, shift_amount))
elif option.lower() == 'b':
for shift_amount in range(26):
print ("using key: " + str(shift_amount))
print(brute(input_message, shift_amount))
else:
print("please enter valid input")
go_again = input("Go again?(Y/N):")
if go_again.lower() == 'n':
break;
Video Information
Views
57
Likes
2
Duration
0:24
Published
Sep 22, 2020
Related Trending Topics
LIVE TRENDSRelated trending topics. Click any trend to explore more videos.
Trending Now