Turing Machine Equivalence Is Not Recognizable 🧠
Using mapping reductions, we prove EQ_TM is neither recognizable nor co-recognizable, highlighting its computational complexity.

Easy Theory
9.9K views • Feb 6, 2021

About this video
Here we use mapping reductions to prove that EQ_TM is not recognizable nor is its complement. We also show that A mapping reduces to B if and only if A-complement mapping reduces to B-complement, which is useful.
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Easy Theory Website: https://www.easytheory.org
Become a member: https://www.youtube.com/channel/UC3VY6RTXegnoSD_q446oBdg/join
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#easytheory
Youtube Live Streaming (Sundays) - subscribe for when these occur.
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Facebook Page: https://www.facebook.com/easytheory/
Facebook group: https://www.facebook.com/groups/easytheory/
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Language Hierarchy Apparel: https://teespring.com/language-hierarchy?pid=2&cid=2122
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If you like this content, please consider subscribing to my channel: https://www.youtube.com/channel/UC3VY6RTXegnoSD_q446oBdg?sub_confirmation=1
Gold Supporters: Micah Wood
Silver Supporters: Timmy Gy
▶SEND ME THEORY QUESTIONS◀
ryan.e.dougherty@icloud.com
▶ABOUT ME◀
I am a professor of Computer Science, and am passionate about CS theory. I have taught many courses at several different universities, including several sections of undergraduate and graduate theory-level classes.
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Video Information
Views
9.9K
Likes
160
Duration
11:40
Published
Feb 6, 2021
User Reviews
4.6
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