Turing Machine for the Language L = a^n b^n | Automata Theory

This document describes the construction of a Turing Machine that recognizes the language L = a^n b^n. The process involves scanning the input tape from left to right, identifying the first 'a', and processing the input to accept strings where the number

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Start at the beginning of the input tape. Scan the tape from left to right, looking for the first "a". If no "a" is found, accept the input and halt. Otherwise, move the head to the right of the "a". Scan the tape from the current position to the right, looking for the first "b". If no "b" is found, reject the input and halt. Otherwise, move the head to the right of the "b". Scan the tape from the current position to the left, looking for the first "a". If no "a" is found, reject the input and halt. Otherwise, move the head to the left of the "a". Repeat steps 3-4 until there are no more "a"s or "b"s to the right or left of the current head position. If the tape is now blank, accept the input and halt. Otherwise, reject the input and halt. Turing Machine Example Turing Machine for a^n b^n Turing Machine no of a followed by no of b Turing Machine Basics Basics of Turing Machine Alan Turing Machine Mathematical model of Computer Introduction to Turing Machine turing machine examples turing machine for 0^n1^n turing machine for 0^2^n turing machine example turing machine for equal number of 0s and 1s turing machine a^nb^n, turing machine english ,turing machine easy example, turing machine easy explain, turing machine in toc, turing machine example, turing machine as enumerator, turing machine in automata, turing machine a^n b^n c^n, turing machine for a^nb^n, turing machine for 0^n1^n,turing machine for palindrome, turing machine for (a+b)*, turing machine, turing machine pdf, turing machine ppt, turing google, toc gate

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