Cryptography: Caesar Cipher Python 3

Give a thumbs up 👍🏻 if my code was useful to you. Showing compilation and execution of my code in Python 3, which is capable of Encrypting, Decrypting, Brute force Attacking using Caesar Cipher cryptography. #python #sublime #caesarcipher #cryptography Develop a single program using any programming language (e.g. Java, Python, C++, etc) that: a. Encrypts and decrypts a message using Cesar’s Cipher. The user encrypting the message is prompted to enter a message and then a key that indicates the displacement. The user decrypting the message is prompted to enter the encrypted message and the key. b. Decrypts and displays all (26) possible solutions. # Writen by Arvin Babaei #Caesar Cipher cryptography code in Python 3 def encrypt(message, key): encrypt_str = '' for ch in message: if ch.isupper(): encrypt_str += chr(ord('A') + ((ord(ch) - ord('A') + key + 26) % 26)) elif ch.islower(): encrypt_str += chr(ord('a') + ((ord(ch) - ord('a') + key + 26) % 26)) else: encrypt_str += ch return encrypt_str def decrypt (message, key): decrypt_str = '' for ch in message: if ch.isupper(): decrypt_str += chr(ord('A') + ((ord(ch) - ord('A') - key + 26) % 26)) elif ch.islower(): decrypt_str += chr(ord('a') + ((ord(ch) - ord('a') - key + 26) % 26)) else: decrypt_str += ch return decrypt_str def brute (message, key): brute_str = '' for ch in message: if ch.isupper(): brute_str += chr(ord('A') + ((ord(ch) - ord('A') - key + 26) % 26)) elif ch.islower(): brute_str += chr(ord('a') + ((ord(ch) - ord('a') - key + 26) % 26)) else: brute_str += ch return brute_str if __name__ == '__main__': while True: input_message = input("Enter message: ") option = input("Encrypt(E) or Decrypt(D) or Brute froce (B)?: ") if option.lower() == 'e': shift_amount = int(input("Enter key: ")) print(encrypt(input_message, shift_amount)) elif option.lower() == 'd': shift_amount = int(input("Enter key: ")) print(decrypt(input_message, shift_amount)) elif option.lower() == 'b': for shift_amount in range(26): print ("using key: " + str(shift_amount)) print(brute(input_message, shift_amount)) else: print("please enter valid input") go_again = input("Go again?(Y/N):") if go_again.lower() == 'n': break;