Designing a Turing Machine for the Language a^n b^n c^n

This guide explains how to construct a Turing machine that accepts strings of the form a^n b^n c^n, where the number of 'a's, 'b's, and 'c's are equal, within the context of automata theory.

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Here's how you can design a Turing machine that accepts the language of strings consisting of 'a's followed by 'b's followed by 'c's where the number of 'a's is equal to the number of 'b's and the number of 'b's is equal to the number of 'c's. Start in state q0 with the tape head positioned at the leftmost symbol of the input string. If the current symbol is 'a', replace it with 'x' and move the tape head to the right. If the current symbol is 'b', replace it with 'y' and move the tape head to the right. If the current symbol is 'c', replace it with 'z' and move the tape head to the right. If the current symbol is blank (i.e., the end of the input string has been reached), move to state q1 and move the tape head back to the leftmost symbol. If the current symbol is 'x' and the next symbol to the right is 'b', replace both symbols with 'B' (blank) and move the tape head one position to the left. If the current symbol is 'y' and the next symbol to the right is 'c', replace both symbols with 'B' (blank) and move the tape head one position to the left. If the current symbol is 'z' and the next symbol to the right is blank, replace both symbols with 'B' (blank) and move the tape head one position to the left. If the current symbol is 'B' and the next symbol to the left is 'x', replace both symbols with 'x' and move the tape head one position to the left. If the current symbol is 'B' and the next symbol to the left is 'y', replace both symbols with 'y' and move the tape head one position to the left. If the current symbol is 'B' and the next symbol to the left is 'z', replace both symbols with 'z' and move the tape head one position to the left. If the current symbol is 'x' and the next symbol to the right is not 'b', move to state qReject. If the current symbol is 'y' and the next symbol to the right is not 'c', move to state qReject. If the current symbol is 'z' and the next symbol to the right is not blank, move to state qReject. If the current symbol is 'x' and there are no more 'b's remaining, move to state q2. If the current symbol is 'y' and there are no more 'c's remaining, move to state qReject. If the current symbol is 'z' and the tape head is at the leftmost symbol, move to state qAccept. The states qReject, qAccept, q1, and q2 are the machine's rejecting, accepting, intermediate, and final states, respectively. Turing Machine Example Turing Machine for a^n b^n c^n Turing Machine no of a followed by no of b Turing Machine Basics Basics of Turing Machine Alan Turing Machine Mathematical model of Computer Introduction to Turing Machine turing machine examples Turing Machine for a^n b^n c^n,Alan Turing Machine,Basics of Turing Machine for 0^n 1^n 2^n,toc,theory of computation, gatelecture, alanturing, thetopgate, topgate,turing machine, turing machine examples a^n b^n c^n, turing machine a^n b^n c^n, turing machine 0^n 1^n 2^n in english, turing machine for a^n b^n c^n, turing machine in toc, turing machine example, turing machine as enumerator, turing machine for a^nb^n c^n in english, turing machine for 0^n1^n 2^n, turing machine for 0^n1^n c^n turing machine for a^nb^nc^2n turing machine for 0^2^n turing machine for a^nb^nc m turing machine example turing machine for equal number of 0s and 1s turing machine for a^nb^nc^n n=0 turing machine a^nb^n, turing machine english, turing machine easy example, turing machine easy explain, turing machine in toc, turing machine example, turing machine as enumerator, turing machine in automata, turing machine a^n b^n c^n, turing machine for a^nb^n, turing machine for 0^n1^n, turing machine for palindrome, turing machine for (a+b)*, turing machine pdf, turing machine ppt, turing google, toc gate, ugc, turing machine for a^nb^nc^n turing machine example - a^n b^n c^n turing machine example turing machine lecture anbncn problem language acceptance problem of turing machine

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Apr 5, 2023

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